bash:one_liners:find_last_day_of_the_month
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I needed to find the last Sunday of the month in relation to a backup script. This is the result:
ncal -h 2>&1 | awk '/Su/ {print $(NF)}'
Finding the amount of days can be done like this:
date -d "`date +%m`/1 + 1 month - 1 day" "+%d";
bash/one_liners/find_last_day_of_the_month.1412579462.txt.gz · Last modified: 2015/08/15 22:56 (external edit)